I tried something earlier to order different vectors by their angle. Would this also work for the recent periodic tag matching?
I would just use the xAxis (1, 0, 0) for the "a" vector.
I would just use the xAxis (1, 0, 0) for the "a" vector.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 | float angle(Vector3 a, Vector3 b) {
float result = 0
if b.y <= 0 {
result = -1 - dotProduct(a, b)
}
if b.y > 0 {
result = 1 + dotProduct(a, b)
}
return result
}
|
Edited by elle
on
If you do this, then you must be sure that vectors a and b is normalized. Depending on how many asset queries will be needed that may be too expensive.
And this will make asset creating a bit more difficult. Because, let's say you want hero asset that faces 45 degree direction. That is in "middle" of 0 and 1. But in your case it is not 0.5. It is 0.7071 = cos(pi/4). For angle variant what is used in stream it is easy - middle of 0 and pi/2 is pi/4.
Also to avoid branches do this:
This assuming sign returns only -1 or +1, but never 0.
And this will make asset creating a bit more difficult. Because, let's say you want hero asset that faces 45 degree direction. That is in "middle" of 0 and 1. But in your case it is not 0.5. It is 0.7071 = cos(pi/4). For angle variant what is used in stream it is easy - middle of 0 and pi/2 is pi/4.
Also to avoid branches do this:
1 | result = sign(b.y) * (1 + dot(a,b)) |
This assuming sign returns only -1 or +1, but never 0.